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21x^2-75x+36=0
a = 21; b = -75; c = +36;
Δ = b2-4ac
Δ = -752-4·21·36
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-51}{2*21}=\frac{24}{42} =4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+51}{2*21}=\frac{126}{42} =3 $
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